Finding factors of a number in python

 

Finding factors of a number in python using loop upto sqrt(n)

In [1]:

import math

number = int (input ('Enter a number: '))

sqrt_value = int (math.sqrt(number))

#print (sqrt_value)

for i in range(1, sqrt_value + 1):

    if number % i == 0:

        if i * i == number:

            print (i, end = ' ')

        else:

            print (i, int(number/i), end = ' ')

Enter a number: 16
1 16 2 8 4 

Finding factors of a number in python

In [2]:

number = int (input ('Enter a number: '))

​

print ('Factors of ', number, ' are: ')

​

for i in range(1, number + 1):

    if number % i == 0:

        print (i, end = ', ')

Enter a number: 12
Factors of  12  are: 
1, 2, 3, 4, 6, 12,