Armstrong number in python

 

Check if a number is Armstrong or not in python

In [1]:

n = 152

num = n

​

count = 0

while n != 0:

    r = n % 10

    count = count + 1

    n = n // 10

n = num

​

sum = 0

while n != 0:

    r = n % 10

    sum = sum + r**count

    n = n // 10

​

if sum == num:

    print (num, ' is a armstrong number.')

else:

    print (num, ' is not a armstrong number.')

152  is not a armstrong number.

Armstrong number from a to b in python

In [3]:

a = int (input("Enter the first value of the range: "))

b = int (input("Enter the last value of the range: "))

​

if a > b:

    a = a + b

    b = a - b

    a = a - b

​

print ("Armstrong numbers from ", a, " to ", b, " are: ")

for n in range(a, b + 1):

    num = n

    digits = 0

    while num != 0:

        digits = digits + 1

        num = num // 10

    num = n

    sum = 0

    while num != 0:

        r = num % 10

        sum = sum + r ** digits

        num = num // 10

    if sum == n:

        print (n, end = " ")

​

Enter the first value of the range: 1
Enter the last value of the range: 1234567
Armstrong numbers from  1  to  1234567  are: 
1 2 3 4 5 6 7 8 9 153 370 371 407 1634 8208 9474 54748 92727 93084 548834